zxxn.net
当前位置:首页 >> 编写一个程序实现如下功能: 1)从键盘上输入n个整... >>

编写一个程序实现如下功能: 1)从键盘上输入n个整...

int jiancha(int *array,int num) { int count = 0; for (int i = 0; i

#include #include #include int main(){ int m,n,i,j,s=0,*ip; printf("请输入正整数m,n:"); scanf("%d%d",&m,&n); ip=maloc(sizeof(int),m*n); printf("请输入数据,以空格或者回车分隔\n"); for(i=0;i

public static void main(String[] args){ System.out.println("输入n,按回车:"); Scanner s = new Scanner(System.in); Integer n = Integer.parseInt(s.next()); Integer re = factorial(1, n); System.out.println(re); } public static I...

public static void main(String[] args){ System.out.println("输入n,按回车:"); Scanner s = new Scanner(System.in); Integer n = Integer.parseInt(s.next()); Integer re = factorial(1, n); System.out.println(re); } public static In...

DATA SEGMENT A DB 'PLEASE INPUT A NUMBER:','$' DATA ENDS CODES SEGMENT ASSUME CS:CODES,DS:DATA START: MOV AX,DATA MOV DS,AX LEA DX,A MOV AH,09H INT 21H MOV AH,01H INT 21H AND AX,01H MOV CX,AX BE:MOV DL,07H MOV AH,02H INT 21H LO...

1 处填写:Sum = 0 2 处填写:n = n - 1

#include#include#include//获取N个0~999的随机数,方便打印阅读int *getRandNum(int n){ int i; int *p; p=(int *)malloc(sizeof(int)*n); srand(time(NULL)); for (i=0; i

编程实现计算n!,也就是n*(n-1)*(n-2)*....*1,可以通过递归函数来实现,具体实现方法: #include int Func(int n){if(n < 2) return 1; else return n*Func(n-1); } void main(){int n =0,m=0; printf("请输入一个正整数:") scanf("%d",&...

import java.util.Scanner; public class InputN { public static void main(String[] args) { Scanner scan = new Scanner(System.in); System.out.print("请输入一个数:"); int n = scan.nextInt(); int sum = 0; if (n

使用for循环即可,代码如下: import java.util.Scanner;public class Demo07 {public static void main(String[] args) {System.out.println("请输入你要求和的数:");//提示用户输入Scanner in = new Scanner(System.in);int max = in.nextInt...

网站首页 | 网站地图
All rights reserved Powered by www.zxxn.net
copyright ©right 2010-2021。
内容来自网络,如有侵犯请联系客服。zhit325@qq.com